A certain man has a mass of 86.0 kg and a density of 996 kg/m3 (excluding the air in his lungs). (a) Calculate his volume (in m3). m3 (b) Find the buoyant force (in N) air exerts on him. N (c) What is the ratio of the buoyant force to his weight? buoyant force weight
![A horizontal underwater plastic meter stick, of mass 407 g and volume 3× 10−4 m3, has two additional forces acting on it. There is a downward force of 2 N applied to the left end of the stick and a 6 N force to the right acting on the extreme right end of the stick. [Hint: The buoyant force on a symmetric body of uniform density acts at the geometric center of the body.] Assume g ≈ 10 N/kg. (a) If we want to suspend the stick from a single cable, how far from the left end of the stick must the force be applied? r = m ( ± 0.01 m) (b) What will be the tension in the cable? T = N ( ± 0.02 N) (c) What angle will the cable make with the vertical? θ = ∘( ± 0.1∘)](https://www.doubtrix.com/uploads/editor/9027192268ugZTcncBjz.png)