Question

Notify Me Bookmark

A disk with surface charge density σ has a hollow center. The inner radius r1 = 0.13 m and the outer radius r2 = 0.24 m. The charge density σ = 1.1×10−6 C/m2. Point P is located along the central axis of symmetry at distance a from the plane of the disk. What is the magnitude of the electric field at point P if a = 0.47 m? E→ = N/C

A disk with surface charge density σ has a hollow center. The inner radius r1 = 0.13 m and the outer radius r2 = 0.24 m. The charge density σ = 1.1×10−6 C/m2. Point P is located along the central axis of symmetry at distance a from the plane of the disk. What is the magnitude of the electric field at point P if a = 0.47 m? E→ = N/C

Image text
A disk with surface charge density σ has a hollow center. The inner radius r 1 = 0.13 m and the outer radius r 2 = 0.24 m . The charge density σ = 1.1 × 10 − 6 C m 2 . Point P is located along the central axis of symmetry at distance a from the plane of the disk. What is the magnitude of the electric field at point P if a = 0.47 m ?
E → = ◻ N / C

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

A disk with surface charge density σ has a hollow center. The inner radius r1 = 0.11 m and the outer radius r2 = 0.24 m. The charge density σ = 1.3×10−6 C/m2. Point P is located along the central axis of symmetry at distance a from the plane of the disk. What is the magnitude of the electric field at point P if a = 0.47 m ? |E→| = N/C

Solution
0 0

Figure below shows a ring of outer radius R = 13.0 cm and inner radius rinner = 0.200R. It has uniform surface charge density σ = 6.20 pC/m2. With V = 0 at infinity, find the electric potential at point P on the central axis of the ring, at distance z = 2.00 R from the center of the ring. (a) Start with the formula for the potential: V = k∫dQ |r→ − r→′| What is your dQ? What is your infinitesimal area element? What are your vectors r and r′ ? What is the distance to point P ? What is dV ? Potential due to a small ring of charge on the disk? (b) Write out the integral that you need to compute to get V. What are the bounds? (c) Once you get an expression for V, solve numerically. (d) Check to see if the units of your expression makes sense for V.
Solution
0 0

Suppose you design an apparatus in which a uniformly charged disk of radius R is to produce an electric field. The field magnitude is most important along the central perpendicular axis of the disk, at a point P at distance 2.30R from the disk (see Figure (a)). Cost analysis suggests that you switch to a ring of the same outer radius R but with inner radius R/2.30 (see Figure (b)). Assume that the ring will have the same surface charge density as the original disk. If you switch to the ring, by what part will you decrease the electric field magnitude at P? (a) (b) Number Units
Solution
0 0