Question

Notify Me Bookmark

A light ray enters a rectangular block of plastic at an angle θ1 = 44.6∘ and emerges at an angle θ2 = 75.9∘, as shown in the figure below. (a) Determine the index of refraction of the plastic. (b) If the light ray enters the plastic at a point L = 50.0 cm from the bottom edge, how long does it take the light ray to travel through the plastic? ns

A light ray enters a rectangular block of plastic at an angle θ1 = 44.6∘ and emerges at an angle θ2 = 75.9∘, as shown in the figure below. (a) Determine the index of refraction of the plastic. (b) If the light ray enters the plastic at a point L = 50.0 cm from the bottom edge, how long does it take the light ray to travel through the plastic? ns

Image text
A light ray enters a rectangular block of plastic at an angle θ 1 = 44.6 ∘ and emerges at an angle θ 2 = 75.9 ∘ , as shown in the figure below. (a) Determine the index of refraction of the plastic. (b) If the light ray enters the plastic at a point L = 50.0 c m from the bottom edge, how long does it take the light ray to travel through the plastic? ns

Detailed Answer

3 0

Please enter your email here. You will get email when this question is answered by our tutor.

Answer
Doubtrix Logo

This Problem has been solved!

You'll get a detailed, step-by-step and expert verified solution.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Login Sign Up
  • Student Reviews:
  • (3)
  • Correct answers (3)
  • Complete solution (3)
  • Step-by-step solution (3)
  • Fully explained (3)

Similar/Related Questions

A light ray enters a rectangular block of plastic at an angle of θ1 = 48.0∘ and emerges at an angle of θ2 = 77.5∘ as shown in the figure below. (a) Determine the index of refraction of the plastic. (b) If the light ray enters the plastic at a point L = 50.0 cm from the bottom edge, what time interval is required for the light ray to travel through the plastic? ns
Solution
3 0

A block of mass m = 2.60 kg is pushed a distance d = 2.60 m along a frictionless horizontal table by a constant applied force of magnitude F = 16.0 N directed at an angle θ = 27.0∘ below the horizontal as shown in the figure below. (a) Determine the work done on the block by the applied force. (b) Determine the work done on the block by the normal force exerted by the table. (c) Determine the work done on the block by the force of gravity. (d) Determine the work done by the net force on the block. J
Solution
0 0

A ball is attached to a cord of length L, which is tied to a frame attached to a truck bed as shown in figure (a), below. The ball-truck system is initially traveling to the right at constant speed vi, with the cord vertical. The truck suddenly stops when it undergoes an inelastic collision with a low wall as shown in figure (b), below. The suspended ball swings through an angle θ. a a (i) b (i) (a) Show that the original speed of the truck can be computed from vi = 2 gL(1−cos⁡(θ)). When the truck stops, the ball begins moving like a -- Select--- ∇. The truck's initial velocity can be derived using ---Select-- . Implementing this derivation method results in which following equation? 12−mvi2+mgL = 0+mgLcos⁡(θ)12−Lvi2+0 = 0+mgL(1−cos⁡(θ))12−mvi2+mg(−L) = 0+mg(−Lcos⁡(θ))12−Lvi2+mgLcos⁡(θ) = 0+mgL Solving this equation for vi gives vi = 2 gL(1−cos⁡(θ)). (b) If the wall is still exerting a horizontal force on the truck when the hanging ball is at its maximum angle forward from the vertical, at what moment does the wall stop exerting a horizontal force? somewhere between the maximum angle forward and the lowest point of the ball the lowest point of the ball somewhere between the lowest point of the ball and the maximum angle backward the maximum angle backward never A ball is attached to a cord of length L, which is tied to a frame attached to a truck bed as shown in figure (a), below. The ball-truck system is initially traveling to the right at constant speed vi, with the cord vertical. The truck suddenly stops when it undergoes an inelastic collision with a low wall as shown in figure (b), below. The suspended ball swings through an angle θ. a a (i) b (i) (a) Show that the original speed of the truck can be computed from vi = 2 gL(1−cos⁡(θ)). When the truck stops, the ball begins moving like a -- Select--- ∇. The truck's initial velocity can be derived using ---Select-- . Implementing this derivation method results in which following equation? 12−mvi2+mgL = 0+mgLcos⁡(θ)12−Lvi2+0 = 0+mgL(1−cos⁡(θ))12−mvi2+mg(−L) = 0+mg(−Lcos⁡(θ))12−Lvi2+mgLcos⁡(θ) = 0+mgL Solving this equation for vi gives vi = 2 gL(1−cos⁡(θ)). (b) If the wall is still exerting a horizontal force on the truck when the hanging ball is at its maximum angle forward from the vertical, at what moment does the wall stop exerting a horizontal force? somewhere between the maximum angle forward and the lowest point of the ball the lowest point of the ball somewhere between the lowest point of the ball and the maximum angle backward the maximum angle backward never

Solution
0 0