A magnet in the form of a cylindrical rod has a length of 4.90 cm and a diameter of 0.920 cm. It has a uniform magnetization of 4.40 × 103 A/m. What is the magnetic dipole moment (J/T)? 1.43 × 10-2 4.32 × 10-3 6.14 × 10-3 9.21 × 10-3 3.07 × 10-2 8.18 × 10-3 4.12 × 10-2 7.67 × 10-3 5.24 × 10-3 5.11 × 10-2

A magnet in the form of a cylindrical rod has a length of 4.90 cm and a diameter of 0.920 cm. It has a uniform magnetization of 4.40 × 103 A/m. What is the magnetic dipole moment (J/T)? 1.43 × 10-2 4.32 × 10-3 6.14 × 10-3 9.21 × 10-3 3.07 × 10-2 8.18 × 10-3 4.12 × 10-2 7.67 × 10-3 5.24 × 10-3 5.11 × 10-2

Image text
A magnet in the form of a cylindrical rod has a length of 4.90 cm and a diameter of 0.920 cm. It has a uniform magnetization of 4.40 × 103 A/m. What is the magnetic dipole moment (J/T)? 1.43 × 10-2 4.32 × 10-3 6.14 × 10-3 9.21 × 10-3 3.07 × 10-2 8.18 × 10-3 4.12 × 10-2 7.67 × 10-3 5.24 × 10-3 5.11 × 10-2

Explanation & Steps

A magnet's strength and direction is a measure of its magnetic dipole moment (µ). The magnetic dipole moment of a cylindrical magnet can be found using the following formula:

µ = MV

Where, magnetic dipole moment (µ) is expressed in A·m² or J/T, the material's magnetization (M) is expressed in A/m, and the magnet's volume (m³) is expressed as V. The volume of cylindrical rod magnet can be calculated and used in above formula to determine magnetic dipole moment.

Detailed Answer

Answer
  • Student Reviews:
  • (2)
  • Correct answers (2)
  • Complete solution (2)
  • Step-by-step solution (2)
  • Fully explained (2)