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A particle has a charge of +2.30 μC and moves from point A to point B, a distance of 0.230 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA − EPEB = +8.20×10−4 J. (a) Find the magnitude of the electric force that acts on the particle. (b) Find the magnitude of the electric field that the particle experiences.

A particle has a charge of +2.30 μC and moves from point A to point B, a distance of 0.230 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA − EPEB = +8.20×10−4 J. (a) Find the magnitude of the electric force that acts on the particle. (b) Find the magnitude of the electric field that the particle experiences.

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A particle has a charge of + 2.30 μ C and moves from point A to point B , a distance of 0.230 m . The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is E P E A − E P E B = + 8.20 × 10 − 4 J . (a) Find the magnitude of the electric force that acts on the particle. (b) Find the magnitude of the electric field that the particle experiences.

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