A particle moving along a straight line has an acceleration which varies according to position as shown. If the velocity of the particle at the position x = −4 ft is v = 5 ft/sec, determine the velocity v when x = 11 ft. Assume x1 = −4 ft, x2 = 5 ft, x3 = 8 ft, x4 = 11 ft, a1 = −3 ft/sec2, a2 = 5 ft/sec2. Answer: v = ft/sec