A particle moving in the x-y plane has a velocity at time t = 5.28 s given by (6.9i + 6.9j) m/s, and at t = 5.38 s its velocity has become (7.07i + 7.03j) m/s. Calculate the magnitude a of its average acceleration during the 0.10-s interval and the angle it makes with the x axis. Answers: a = m/s2 θ =

A particle moving in the x-y plane has a velocity at time t = 5.28 s given by (6.9i + 6.9j) m/s, and at t = 5.38 s its velocity has become (7.07i + 7.03j) m/s. Calculate the magnitude a of its average acceleration during the 0.10-s interval and the angle it makes with the x axis. Answers: a = m/s2 θ =

Image text
A particle moving in the x -y plane has a velocity at time t = 5.28 s given by ( 6.9 i + 6.9 j ) m / s , and at t = 5.38 s its velocity has become ( 7.07 i + 7.03 j ) m / s . Calculate the magnitude a of its average acceleration during the 0.10 -s interval and the angle it makes with the x axis.
Answers: a = i m / s 2 θ = i

Detailed Answer

Answer
  • Student Reviews:
  • (3)
  • Correct answers (3)
  • Complete solution (3)
  • Step-by-step solution (3)
  • Fully explained (3)