A particle moving in the x-y plane has a velocity at time t = 5.28 s given by (6.9i + 6.9j) m/s, and at t = 5.38 s its velocity has become (7.07i + 7.03j) m/s. Calculate the magnitude a of its average acceleration during the 0.10-s interval and the angle it makes with the x axis. Answers: a = m/s2 θ =
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