Question

Notify Me Bookmark

A particle with charge 5.0 μC is placed at the corner of a cube. The total electric flux through all sides of the cube is: 0 N⋅m2/C 7.1×104 N⋅m2/C 9.4×104 N⋅m2/C 1.4×105 N⋅m2/C 5.6×105 N⋅m2/C

A particle with charge 5.0 μC is placed at the corner of a cube. The total electric flux through all sides of the cube is: 0 N⋅m2/C 7.1×104 N⋅m2/C 9.4×104 N⋅m2/C 1.4×105 N⋅m2/C 5.6×105 N⋅m2/C

Image text
A particle with charge 5.0 μ C is placed at the corner of a cube. The total electric flux through all sides of the cube is: 0 N ⋅ m 2 / C 7.1 × 10 4 N ⋅ m 2 / C 9.4 × 10 4 N ⋅ m 2 / C 1.4 × 10 5 N ⋅ m 2 / C 5.6 × 10 5 N ⋅ m 2 / C

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

A particle of charge q = 95 μC is placed at a corner of a Gaussian cube of edge a = 11 cm. What is the flux through (a) each cube face forming that corner and (b) each of the other cube faces? (a) Number Units (b) Number Units
Solution
0 0

The cube in the figure (Figure 1) has sides of length L = 10.0 cm. The electric field is uniform, has a magnitude E = 4.00×10 3 N/C, and is parallel to the xy-plane at an angle of 36.9∘ measured from the +x - axis toward the +y - axis. Figure 1 of 1 Part A What is the electric flux through the cube face S1? AΣϕ Φ1 = N⋅m2/C? Submit Request Answer Part B What is the electric flux through the cube face S2? Aϕ ? Φ2 = N⋅m2/C Submit Request Answer Part C What is the electric flux through the cube face S3? AΣϕ Φ3 = N⋅m2/C? Submit Request Answer Part D What is the electric flux through the cube face S4? AΣϕ Φ4 = N⋅m2/C? Submit Request Answer Part E What is the electric flux through the cube face S5? AΣϕ Φ5 = N⋅m2/C Submit Request Answer Part F What is the electric flux through the cube face S6? AΣϕ Φ6 = N⋅m2/C Submit Request Answer Part G What is the total electric flux through all faces of the cube? AΣϕ Φtotal = N⋅m2/C Submit Request Answer The cube in the figure (Figure 1) has sides of length L = 10.0 cm. The electric field is uniform, has a magnitude E = 4.00×10 3 N/C, and is parallel to the xy-plane at an angle of 36.9∘ measured from the +x - axis toward the +y - axis. Figure 1 of 1 Part A What is the electric flux through the cube face S1? AΣϕ Φ1 = N⋅m2/C? Submit Request Answer Part B What is the electric flux through the cube face S2? Aϕ ? Φ2 = N⋅m2/C Submit Request Answer Part C What is the electric flux through the cube face S3? AΣϕ Φ3 = N⋅m2/C? Submit Request Answer Part D What is the electric flux through the cube face S4? AΣϕ Φ4 = N⋅m2/C? Submit Request Answer Part E What is the electric flux through the cube face S5? AΣϕ Φ5 = N⋅m2/C Submit Request Answer Part F What is the electric flux through the cube face S6? AΣϕ Φ6 = N⋅m2/C Submit Request Answer Part G What is the total electric flux through all faces of the cube? AΣϕ Φtotal = N⋅m2/C Submit Request Answer The cube in the figure (Figure 1) has sides of length L = 10.0 cm. The electric field is uniform, has a magnitude E = 4.00×10 3 N/C, and is parallel to the xy-plane at an angle of 36.9∘ measured from the +x - axis toward the +y - axis. Figure 1 of 1 Part A What is the electric flux through the cube face S1? AΣϕ Φ1 = N⋅m2/C? Submit Request Answer Part B What is the electric flux through the cube face S2? Aϕ ? Φ2 = N⋅m2/C Submit Request Answer Part C What is the electric flux through the cube face S3? AΣϕ Φ3 = N⋅m2/C? Submit Request Answer Part D What is the electric flux through the cube face S4? AΣϕ Φ4 = N⋅m2/C? Submit Request Answer Part E What is the electric flux through the cube face S5? AΣϕ Φ5 = N⋅m2/C Submit Request Answer Part F What is the electric flux through the cube face S6? AΣϕ Φ6 = N⋅m2/C Submit Request Answer Part G What is the total electric flux through all faces of the cube? AΣϕ Φtotal = N⋅m2/C Submit Request Answer The cube in the figure (Figure 1) has sides of length L = 10.0 cm. The electric field is uniform, has a magnitude E = 4.00×10 3 N/C, and is parallel to the xy-plane at an angle of 36.9∘ measured from the +x - axis toward the +y - axis. Figure 1 of 1 Part A What is the electric flux through the cube face S1? AΣϕ Φ1 = N⋅m2/C? Submit Request Answer Part B What is the electric flux through the cube face S2? Aϕ ? Φ2 = N⋅m2/C Submit Request Answer Part C What is the electric flux through the cube face S3? AΣϕ Φ3 = N⋅m2/C? Submit Request Answer Part D What is the electric flux through the cube face S4? AΣϕ Φ4 = N⋅m2/C? Submit Request Answer Part E What is the electric flux through the cube face S5? AΣϕ Φ5 = N⋅m2/C Submit Request Answer Part F What is the electric flux through the cube face S6? AΣϕ Φ6 = N⋅m2/C Submit Request Answer Part G What is the total electric flux through all faces of the cube? AΣϕ Φtotal = N⋅m2/C Submit Request Answer The cube in the figure (Figure 1) has sides of length L = 10.0 cm. The electric field is uniform, has a magnitude E = 4.00×10 3 N/C, and is parallel to the xy-plane at an angle of 36.9∘ measured from the +x - axis toward the +y - axis. Figure 1 of 1 Part A What is the electric flux through the cube face S1? AΣϕ Φ1 = N⋅m2/C? Submit Request Answer Part B What is the electric flux through the cube face S2? Aϕ ? Φ2 = N⋅m2/C Submit Request Answer Part C What is the electric flux through the cube face S3? AΣϕ Φ3 = N⋅m2/C? Submit Request Answer Part D What is the electric flux through the cube face S4? AΣϕ Φ4 = N⋅m2/C? Submit Request Answer Part E What is the electric flux through the cube face S5? AΣϕ Φ5 = N⋅m2/C Submit Request Answer Part F What is the electric flux through the cube face S6? AΣϕ Φ6 = N⋅m2/C Submit Request Answer Part G What is the total electric flux through all faces of the cube? AΣϕ Φtotal = N⋅m2/C Submit Request Answer

Solution
2 0

50 μC of negative charge is placed on an insulating pith ball and lowered into an insulating plastic container, suspended from an insulating thread attached to the lid of the box. After the box is entirely sealed, the electric flux through the sides of the box is: 5.65×106 N⋅m2/C. 5.65×105 N⋅m2/C. −5.65×105 N⋅m2/C. Can't tell unless the dimensions of the box are given. −5.65×106 N⋅m2/C
Solution
0 0