Question

Notify Me Bookmark

A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.280 Hz. The pendulum has a mass of 2.00 kg, and the pivot is located 0.400 m from the center of mass. Determine the moment of inertia of the pendulum about the pivot point. kg⋅m2

A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.280 Hz. The pendulum has a mass of 2.00 kg, and the pivot is located 0.400 m from the center of mass. Determine the moment of inertia of the pendulum about the pivot point. kg⋅m2

Image text
A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.280 H z . The pendulum has a mass of 2.00 k g , and the pivot is located 0.400 m from the center of mass. Determine the moment of inertia of the pendulum about the pivot point. k g ⋅ m 2

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.490 Hz. The pendulum has a mass of 2.40 kg, and the pivot is located 0.300 m from the center of mass. Determine the moment of inertia of the pendulum about the pivot point. kg⋅m2

Solution
0 0

The truck with a ladder plotted in Fig. 5 starts from rest (and accelerates to the left) with an acceleration of 7 m/s2. The ladder of mass m = 10 kg, which is the rigid body of interest in this problem, can be modeled as a uniform slender rod that is hinged at point A and supported at point B. As a consequence, the center of mass G of the ladder is located at the midpoint of the rod. Any friction in this problem is supposed to be small enough to be neglected. a) Determine the minimum linear acceleration amin of the truck such that the ladder loses contact at point B, i. e. the normal force NB at B vanishes, and starts to rotate about point A. Do so by determining the sum of the moments about point A, and verify that for the given acceleration of the truck, the ladder will in fact lose contact at point B. b) Determine the mass moment of inertia I¯ of the ladder associated with its center of mass G. c) Use the result found in Part b) and employ the concept of relative acceleration expressed in terms of a normal-tangential coordinate system to determine the initial angular acceleration vector α of the ladder. Figure 5: A truck with a ladder accelerating from rest to the left and measurements.
Solution
0 0

In the figure, a physical pendulum consists of a uniform solid disk (of radius R = 29.2 cm) supported in a vertical plane by a pivot located a distance d = 8.46 cm from the center of the disk. The disk is displaced by a small angle and released. What is the period of the resulting simple harmonic motion? Number Units
Solution
0 0