A projectile is launched at point O in the x−y plane with the initial velocity and angle, as shown. Simultaneously, an airplane is flying in x−y plane in a straight line at an angle of 30-deg from the x-axis with a constant velocity of 480 ft/s. At the instant of 4 -seconds after the launch of the ball, calculate the following: a) The magnitude of the resultant velocity of the ball as measured by the pilot, b) The direction (measured counterclockwise from the x-axis) of the resultant velocity of the ball as measured by the pilot.
![A projectile is launched of the top of a tower with an initial velocity of 70 [m/s] at an angle of 37 degrees with respect to the horizontal axis. The tower is 30 [m], meaning the projectile is launched at a height of 30 [m] above the ground. To simplify the math in the problem use: g = 10 m/s2 sin(37degrees) = 0.6 cos(37degrees) = 0.8 See figure below: What is the maximum height achieved by the projectile as measured from the ground? 118.2 [m] 188.2 [m] 144.1 [m] 88.2 [m] 44.1 [m]](https://www.doubtrix.com/uploads/editor/6994826109BUGcvpaZzG.jpg)
