Question

Notify Me Bookmark

A proton moves through a region containing a uniform electric field given by E→ = 58.0 j^ V/m and a uniform magnetic field B→ = (0.200 i^ + 0.300 j^ + 0.400 k^) T. Determine the acceleration of the proton when it has a velocity v→ = 230 i^ m/s a→ = m/s2

A proton moves through a region containing a uniform electric field given by E→ = 58.0 j^ V/m and a uniform magnetic field B→ = (0.200 i^ + 0.300 j^ + 0.400 k^) T. Determine the acceleration of the proton when it has a velocity v→ = 230 i^ m/s a→ = m/s2

Image text
A proton moves through a region containing a uniform electric field given by E → = 58.0 j ^ V / m and a uniform magnetic field B → = ( 0.200 i ^ + 0.300 j ^ + 0.400 k ^ ) T . Determine the acceleration of the proton when it has a velocity v → = 230 i ^ m / s
a → =
m / s 2

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

(a) An electron moves through a uniform electric field E→ = (2.00 i^ + 5.90 j^) V/m and a uniform magnetic field B→ = 0.400 k^ T. Determine the acceleration of the electron when it has a velocity v→ = 12.0 i^ m/s. (Give each component in m/s2.) ax = m/s2 ay = m/s2 az = m/s2 m/s2 (b) What If? For the electron moving along the x-axis in the fields in part (a), what speed (in m/s) would result in the electron also experiencing an acceleration directed along the x-axis? m/s
Solution
0 0

An electron moves through a uniform magnetic field. The magnetic field is given by B→ = (0.00i^ − 90.5j^ + 50.9k^) mT. At a moment in time when the velocity is v→ = (0.00i^ + vyj^ + 98400.00k^) m/s, the magnetic force acting on the electron is F→ = (2.59i^ + 0.00j^ + 0.00k^)×10−16 N. What is the value of vy? m/s
Solution
0 0

A positively charged particle of mass m and charge q is released from rest in a uniform electric field, E→ = (10i^) V/m. The particle, after travelling 2 s in this electric field, enters a region that is free from electric field but has a steady and uniform magnetic field, B→ = (−4k^) T. What will be the radius of the circular path (in meters) and the direction of angular velocity of the particle in this region? (Select the closest number among the following choices.) (Note: an incorrect answer will be penalized 2 pts.) a) 5.0; k^ b) 0.2; k^ c) 0.2; −k^ d) 2.0; k^ e) 5.0; −k^
Solution
0 0