Question

Notify Me Bookmark

A solid sphere with a mass of 13.2 kg and a radius of 0.29 m spins about its center with an initial angular velocity of 51.2 rad/s. If it slows at a rate of −2.6 rad/s2. what is its rotational kinetic energy after 6.09 seconds? The moment of inertia of a solid sphere is I = 0.4 MR2

A solid sphere with a mass of 13.2 kg and a radius of 0.29 m spins about its center with an initial angular velocity of 51.2 rad/s. If it slows at a rate of −2.6 rad/s2. what is its rotational kinetic energy after 6.09 seconds? The moment of inertia of a solid sphere is I = 0.4 MR2

Image text
A solid sphere with a mass of 13.2 k g and a radius of 0.29 m spins about its center with an initial angular velocity of 51.2 r a d / s . If it slows at a rate of − 2.6 r a d / s 2 . what is its rotational kinetic energy after 6.09 seconds?
The moment of inertia of a solid sphere is 1 = 0.4 M R 2 ◻

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

A solid sphere with a mass of M = 1.00 kilogram and a radius of R = 6 centimeters starts at rest and rolls down a ramp that is 1.00 meter long and makes a 30∘ angle with the horizontal. The ramp connects with a horizontal track where a second, identical ball is located 1.00 meter away from the junction of the two sections. The two spheres collide. The rotational inertia for a solid sphere is I = 25 MR2. Show complete work for all answers. Assume that friction is negligible. a. Determine the time that elapses between the release of the sphere at the top of the ramp and the collision between the two spheres. b. Determine the angular momentum (both magnitude and direction) of the sphere when it has reached the bottom of the ramp. c. Calculate the linear velocity of the center of mass of the system consisting of both spheres after the collision.
Solution
0 0

A crane is made from a long, horizontal arm with mass m = 2.41×104 kg and length L = 52.0 m. The crane arm is supported by a vertical tower positioned halfway along the arm as shown in the figure below. The arm is free to rotate horizontally about the axis of the tower. The moment of inertia of a uniform rod with mass m and length L pivoted about its centre is given by Irod = 112 mL2. L Part 1) The crane lifts a mass M = 1070 kg at the end of the arm on one side of the tower. To keep the crane balanced, a counterweight of mass Mc = 5420 kg is placed on the arm on the opposite side of the tower to mass M. How far from the tower should the counterweight be placed such that the centre of mass for the arm and both masses is directly over the tower? x = m Part 2) What is the moment of inertia of the crane about the axis of the tower? Include the contributions of the horizontal arm, the mass and the counterweight. I = kg m2 Part 3) A net torque of magnitude τ = 6660 Nm is applied to the crane. If the crane starts at rest, what is its angular velocity after t = 30.0 s ? ω = rad s−1
Solution
0 0

A playground carousel is rotating counterclockwise about its center on frictionless bearings. A person standing still on the ground grabs onto one of the bars on the carousel very close to its outer edge and climbs aboard. Thus, this person begins with an angular speed of zero and ends up with a nonzero angular speed, which means that he underwent a counterclockwise angular acceleration. The carousel has a radius of 1.52 m, an initial angular speed of 3.23 rad/s, and a moment of inertia of 128 kg⋅m2. The mass of the person is 41.5 kg. Find the final angular speed of the carousel after the person climbs aboard. ωf =
Solution
0 0