Question

Notify Me Bookmark

A uniform bar of mass M = 28.2 kg has a mass m = 10.4 kg attached three quarters of the way from its left end. The bar is supported in equilibrium by two vertical ropes at the left and right ends under tension T1 and T2 respectively. The bar has a length L = 4.11 m. This is shown in the diagram. (The input below will accept answers with no more than 1% variation from the correct value.) What is T1? N What is T2? N

A uniform bar of mass M = 28.2 kg has a mass m = 10.4 kg attached three quarters of the way from its left end. The bar is supported in equilibrium by two vertical ropes at the left and right ends under tension T1 and T2 respectively. The bar has a length L = 4.11 m. This is shown in the diagram. (The input below will accept answers with no more than 1% variation from the correct value.) What is T1? N What is T2? N

Image text
A uniform bar of mass M = 28.2 k g has a mass m = 10.4 k g attached three quarters of the way from its left end. The bar is supported in equilibrium by two vertical ropes at the left and right ends under tension T 1 and T 2 respectively. The bar has a length L = 4.11 m . This is shown in the diagram. (The input below will accept answers with no more than 1 % variation from the correct value.) What is T 1 ? N What is T 2 ? ◻ N

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

A crane is made from a long, horizontal arm with mass m = 2.41×104 kg and length L = 52.0 m. The crane arm is supported by a vertical tower positioned halfway along the arm as shown in the figure below. The arm is free to rotate horizontally about the axis of the tower. The moment of inertia of a uniform rod with mass m and length L pivoted about its centre is given by Irod = 112 mL2. L Part 1) The crane lifts a mass M = 1070 kg at the end of the arm on one side of the tower. To keep the crane balanced, a counterweight of mass Mc = 5420 kg is placed on the arm on the opposite side of the tower to mass M. How far from the tower should the counterweight be placed such that the centre of mass for the arm and both masses is directly over the tower? x = m Part 2) What is the moment of inertia of the crane about the axis of the tower? Include the contributions of the horizontal arm, the mass and the counterweight. I = kg m2 Part 3) A net torque of magnitude τ = 6660 Nm is applied to the crane. If the crane starts at rest, what is its angular velocity after t = 30.0 s ? ω = rad s−1
Solution
0 0

A beam resting on two pivots has a length of L = 6.00 m and mass M = 91.0 kg. The pivot under the left end exerts a normal force n1 on the beam, and the second pivot placed a distance ℓ = 4.00 m from the left end exerts a normal force n2. A woman of mass m = 58.5 kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip. (i) (a) Sketch a free-body diagram, labeling the gravitational and normal forces acting on the beam and placing the woman x meters to the right of the first pivot, which is the origin. (Submit a file with a maximum size of 1 MB.) Choose file no file selected This answer has not been graded yet. (b) Where is the woman when the normal force n1 is the greatest? x = m (c) What is n1 when the beam is about to tip? N (d) Use the force equation of equilibrium to find the value of n2 when the beam is about to tip. N (e) Using the result of part (c) and the torque equilibrium equation, with torques computed around the second pivot point, find the woman's position when the beam is about to tip. x = m (f) Check the answer to part (e) by computing torques around the first pivot point. x = m Except for possible slight differences due to rounding, is the answer the same? Yes No
Solution
0 0

In the figure shown below, one end of a cord is attached to the floor and the other end is attached to a small set of essentially massless wheels through a slot in a track on which the wheels roll without friction. As a result of this arrangement, the upper end of the cord is essentially free. At equilibrium, the cord is vertical and motionless. When it carries a small amplitude wave, the cord is under a uniform tension of 1.20 N. The cord has a mass of 5.80 g and a length of 85.0 cm. (a) Find the speed (in m/s) of the transverse waves in the cord. m/s (b) The cord's vibration possibilities are a set of standing-wave states, each with a node at the fixed bottom end and an antinode at the free top end. Find the node-antinode distances (in m) for the first three harmonics. Enter your answers from the lowest to the highest harmonic. m m m (c) Find the frequency (in Hz) of each of these states. (Enter your answers from simplest to more complicated.) Hz Hz Hz (d) What If? The wheels get stuck on the track and are unable to move, hence making the cart stationary. Determine the node-antinode distance (in m) and frequency of vibration (in Hz) for the third harmonic. distance m frequency Hz
Solution
0 0