Question

Notify Me Bookmark

A uniform electric field of magnitude 280 V/m is directed in the negative y direction as shown in the figure below. The coordinates of point A are (-0.500, -0.700) m, and those of point (B) are (0.550, 0.650)m. Calculate the electric potential difference VB - VA using the dashed-line path. V

A uniform electric field of magnitude 280 V/m is directed in the negative y direction as shown in the figure below. The coordinates of point A are (-0.500, -0.700) m, and those of point (B) are (0.550, 0.650)m. Calculate the electric potential difference VB - VA using the dashed-line path. V

Image text
A uniform electric field of magnitude 280 V / m is directed in the negative y direction as shown in the figure below. The coordinates of point A are ( − 0.500 , − 0.700 ) m , and those of point (B) are ( 0.550 , 0.650 ) m . Calculate the electric potential difference V B − V A using the dashed-line path. ◻ V

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

A uniform electric field of magnitude 290 V/m is directed in the negative y direction as shown in the figure below. The coordinates of point (A) are (−0.500, −0.650) m, and those of point (B) are (0.450, 0.600) m. Calculate the electric potential difference VB−VA using the dashed-line path. V
Solution
0 0

A uniform electric field E→ = −3.3 N/Ci^ points in the negative x direction as shown in the figure. The x and y coordinates of points A, B, and C are given on the diagram (in meters). (Figure 1) Determine the differences in potential VBA = VB−VA, VCB = VC−VB, and VCA = VC−VA. Express your answers using two significant figures separated by commas. Submit Request Answer Provide Feedback Figure 1 of 1
Solution
0 0

A 150 V battery is connected across two parallel metal plates of area 28.5 cm2 and separation 9.20 mm. A beam of alpha particles (charge +2e, mass 6.64×10−27 kg ) is accelerated from rest through a potential difference of 1.75 kV and enters the region between the plates perpendicular to the electric field, as shown in (Figure 1). Figure 1 of 1 Part A What magnitude of magnetic field is needed so that the alpha particles emerge undeflected from between the plates? Express your answer with the appropriate units. Submit Request Answer Part B What is the direction of this magnetic field? The magnetic field is directed into the page. The magnetic field is directed out of the page. The magnetic field is directed upward. The magnetic field is directed downward. Submit Request Answer Request Answer

Solution
0 0