According to Equation 20.7, an ac voltage V is given as a function of

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According to Equation 20.7, an ac voltage V is given as a function of time t by V = Vosin⁡2πft, where Vo is the peak voltage and f is the frequency (in hertz). For a frequency of 48.4 Hz, what is the smallest value of the time at which the voltage equals one-half of the peak-value?

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According to Equation 20.7, an ac voltage

V

is given as a function of time

t

V = V_{o} \sin 2 π f t

, where

V_{o}

is the peak voltage and

f

is the frequency (in hertz). For a frequency of 48.4 Hz , what is the smallest value of the time at which the voltage equals one-half of the peak-value?