Question

Notify Me Bookmark

An electron initially at rest, is placed at electric field of 4.0×104 N/C directed to the west. The distance between the plates is 2.0 cm a) What is the acceleration of the electron due to the electric field? b) What will be the speed of the electron after it leaves the hole. Show the sketch of the two plates?

An electron initially at rest, is placed at electric field of 4.0×104 N/C directed to the west. The distance between the plates is 2.0 cm a) What is the acceleration of the electron due to the electric field? b) What will be the speed of the electron after it leaves the hole. Show the sketch of the two plates?

Image text
An electron initially at rest, is placed at electric field of 4.0 × 10 4 N / C directed to the west. The distance between the plates is 2.0 cm a) What is the acceleration of the electron due to the electric field? b) What will be the speed of the electron after it leaves the hole. Show the sketch of the two plates?

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

A beam of electrons is created by an electron gun and they move horizontally with a speed of 3.3×107 m/s. The electrons enter a 2.0 cm long gap between the two parallel plates where the electric field intensity is 5.0×104 N/C down. See the diagram below. a) Determine the time to cross the plates. b) Determine the magnitude and direction of the acceleration in the region between the plates. c) Determine the final velocity of the electron as it leaves the plates (both magnitude and direction).
Solution
0 0

A particle possessing q = 7.25 μC of charge and a mass of m = 6.55 g is fired at a speed of v = 255 cm/s between two horizontal charged plates of length L = 44.7 cm. Assume that the electric field between the plates is uniform and has a constant value of E = 1770 N/C, directed upwards. Calculate the distance y by which the charge falls below a straight-line path when it reaches the end of the plates. Assume a gravitational acceleration of g = 9.81 m/s2. What field strength will allow the particle to pass between the plates along a straight path? field strength: N/C
Solution
0 0

A uniform electric field exists in a region between two oppositely charged plates. An electron is released from rest at the surface of the negatively charged plate and strikes the surface of the opposite plate, 2.6 cm away, in a time 1.4×10−8 s. (a) What is the speed of the electron as it strikes the second plate? (b) What is the magnitude of the electric field? (a) Number Units (b) Number Units
Solution
0 0