An electron with a horizontal speed of 2500000 m/s and no vertical component of velocity passes through two horizontal parallel plates, as shown. The magnitude of the electric field between the plates is 180 N/C. The plates are 5 cm long. Calculate the angle to the horizontal, θ (in degrees), that the electron would pass through the plates with. Attach your work for full marks. Answers within 3% of the true answer will be considered correct. Your Answer:

An electron with a horizontal speed of 2500000 m/s and no vertical component of velocity passes through two horizontal parallel plates, as shown. The magnitude of the electric field between the plates is 180 N/C. The plates are 5 cm long. Calculate the angle to the horizontal, θ (in degrees), that the electron would pass through the plates with. Attach your work for full marks. Answers within 3% of the true answer will be considered correct. Your Answer:

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An electron with a horizontal speed of 2500000 m / s and no vertical component of velocity passes through two horizontal parallel plates, as shown. The magnitude of the electric field between the plates is 180 N / C . The plates are 5 c m long. Calculate the angle to the horizontal, θ (in degrees), that the electron would pass through the plates with.
Attach your work for full marks. Answers within 3 % of the true answer will be considered correct.
Your Answer:

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