Question

Notify Me Bookmark

An isolated charged soap bubble of radius R0 = 4.25 cm has a potential of V0 = 323.0 V at its surface. If the bubble shrinks to a radius that is 43.0% of the initial radius, by how much ΔU does its electrostatic potential energy change? ΔU = J Assume that the charge on the bubble is spread evenly over the surface, and that the total charge on the bubble remains constant. Use k = 8.99×109 N⋅m2/C2 for the Coulomb force constant.

An isolated charged soap bubble of radius R0 = 4.25 cm has a potential of V0 = 323.0 V at its surface. If the bubble shrinks to a radius that is 43.0% of the initial radius, by how much ΔU does its electrostatic potential energy change? ΔU = J Assume that the charge on the bubble is spread evenly over the surface, and that the total charge on the bubble remains constant. Use k = 8.99×109 N⋅m2/C2 for the Coulomb force constant.

Image text
An isolated charged soap bubble of radius R 0 = 4.25 cm has a potential of V 0 = 323.0 V at its surface.
If the bubble shrinks to a radius that is 43.0 % of the initial radius, by how much Δ U does its electrostatic potential energy change?
Δ U = ◻ J
Assume that the charge on the bubble is spread evenly over the surface, and that the total charge on the bubble remains constant. Use k = 8.99 × 10 9 N ⋅ m 2 / C 2 for the Coulomb force constant.

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

A ring of charge is centered at the origin in the vertical direction. The ring has a charge density of λ = 4.48×10−6 C/m and a radius of R = 2.01 cm. Find the total electric field, E, of the ring at the point P = (1.10 m, 0.00 m). The Coulomb force constant is k = 1 /(4πϵ0) = 8.99×109 N⋅m2/C2. E = N/C Find the expression for the electric field, E∞, of the ring as the point P becomes very far from the ring (x ≫ R) in terms of the radius R, the distance x, the total charge on the ring⁡ q, and the constant k = 1/(4πϵ0).

Solution
0 0

A ring of charge is centered at the origin in the vertical direction. The ring has a charge density of λ = 3.99×10−6 C/m and a radius of R = 3.55 cm. Find the total electric field, E, of the ring at the point P = (2.02 m, 0.00 m). The Coulomb force constant is k = 1/(4πϵ0) = 8.99×109 N⋅m2 /C2. E = N/C Find the expression for the electric field, E∞, of the ring as the point P becomes very far from the ring (x ≫ R) in terms of the radius R, the distance x, the total charge on the ring q, and the constant k = 1/(4πϵ0). E∞ =
Solution
0 0

Two identical, positively-charged conducting spheres are fixed in space. The spheres are 45.6 cm apart (center to center) and repel each other with an electrostatic force of F1 = 0.0645 N. A thin conducting wire then connects the spheres, enabling the redistribution of charge on the spheres. When the wire is removed, the spheres still repel, but with a force of F2 = 0.100 N. Using this information, determine the initial charges q1 and q2 on the spheres. Enter the smaller charge as q1. The Coulomb force constant is k = 1/(4πϵ0) = 8.99×109 N⋅m2/C2. q1 = C q2 =
Solution
0 0