Question

Notify Me Bookmark

An object is sent into a projectile (parabolic motion) from h = 1.35 m above ground level with an initial velocity of v0 = 2.5 m/s and at an angle of θ = +28∘. a) Find the total time (from A → B → C) to reach the ground level? (4 points) b) Find the maximum height object can reach from ground level (Y displacement from A→B)? (3 points) c) Find Y velocity component of the object at point C? (3 points)

An object is sent into a projectile (parabolic motion) from h = 1.35 m above ground level with an initial velocity of v0 = 2.5 m/s and at an angle of θ = +28∘. a) Find the total time (from A → B → C) to reach the ground level? (4 points) b) Find the maximum height object can reach from ground level (Y displacement from A→B)? (3 points) c) Find Y velocity component of the object at point C? (3 points)

Image text
An object is sent into a projectile (parabolic motion) from h = 1.35 m above ground level with an initial velocity of v 0 = 2.5 m / s and at an angle of θ = + 28 ∘ . a) Find the total time (from A → B → C ) to reach the ground level? (4 points) b) Find the maximum height object can reach from ground level (Y displacement from A → B )? (3 points) c) Find Y velocity component of the object at point C? (3 points)

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

A ship maneuvers to a position at a horizontal distance Δx1 = 2.50×103 m from an island's mountain peak with maximum height hM = 1.80×103 m, and fires a projectile at an enemy ship on the other side of the peak, which is at a horizontal distance Δx2 = 6.10×102 m from the peak, as illustrated below. The projectile is shot with an initial velocity vi = 2.50×102 m/s at an angle θ = 75.0∘. Assume no air resistance and ay = −g = −9.80 m/s2. a) What type of motion does the projectile undergo? What type of trajectory does it have? b) Find the maximum height hmax reached by the projectile. c) Find the total time of flight in the air Δttot just before the projectile hits the water surface. d) How close horizontally to the enemy ship does the projectile land? e) How close vertically does the projectile come to the peak?
Solution
0 0

The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 23.5 m/s is h = 2 + 23.5t − 4.9t2 after t seconds. (a) Find the velocity (in m/s ) after t seconds. v(t) = Find the velocity (in m/s ) after 2 seconds and after 4 seconds. v(2) = m/s v(4) = m/s (b) What is the value (in m/s ) of v(t) when the projectile reaches its maximum height? v(t) = m/s When (in s) does the projectile reach its maximum height? (Round your answer to two decimal places.) s (c) What is the maximum height (in m)? (Round your answer to two decimal places.) m (d) When (in s) does it hit the ground? (Round your answer to two decimal places.) S (e) With what velocity (in m/s ) does it hit the ground? (Round your answer to two decimal places.) m/s
Solution
0 0

During fireworks display, a shell is shot into the air with an initial speed of |v→0| = 70 m/s at an angle of 75.0∘ above the horizontal, as illustrated on the figure. The fuse is timed to ignite the shell just as it reaches its highest point above the ground. Compute the horizontal v0 x and vertical v0 y components of the initial velocity. (2 points)Using the correct equation compute the maximum height h that the shell will reach. (2 points)Using the correct equation compute the time the shell will take to reach the maximum height h. (2 points)Compute the horizontal displacement Δx. (2 points)
Solution
0 0