Question

Notify Me Bookmark

As a loop of wire with a resistance of 10 Ω moves in a non-uniform magnetic field, it loses kinetic energy at a uniform rate of 5 mJ/s. The induced emf in the loop is: 0 V 0.22 V 0.28 V 2.0 V cannot be calculated from the given data

As a loop of wire with a resistance of 10 Ω moves in a non-uniform magnetic field, it loses kinetic energy at a uniform rate of 5 mJ/s. The induced emf in the loop is: 0 V 0.22 V 0.28 V 2.0 V cannot be calculated from the given data

Image text
As a loop of wire with a resistance of 10 Ω moves in a non-uniform magnetic field, it loses kinetic energy at a uniform rate of 5 mJ/s. The induced emf in the loop is: 0 V 0.22 V 0.28 V 2.0 V cannot be calculated from the given data

Explanation & Steps

According to Faraday's Law of Electromagnetic induction, electromotive force (EMF) or voltage in a conductor can be induced by a fluctuating magnetic field. The induced electromotive force (EMF) in a closed circuit is determined is given by negative rate of change of the magnetic flux flowing through the circuit and mathematically can be represented as ε = - dΦ/dt. Where, the induced electromagnetic field (EMF) is represented by ε, the change in magnetic flux change is represented by dΦ/dt. The negative sign indicates that the induced EMF's opposes the change in magnetic flux.

The induced emf results in power dissipation in resistance of wire. To calculate the value of induced emf, use relation between power dissipated in a resistance, induced emf and resistance of wire.

Detailed Answer

1 0

Please enter your email here. You will get email when this question is answered by our tutor.

Answer
Doubtrix Logo

This Problem has been solved!

You'll get a detailed, step-by-step and expert verified solution.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Login Sign Up
  • Student Reviews:
  • (1)
  • Correct answers (1)
  • Complete solution (1)
  • Step-by-step solution (1)
  • Fully explained (1)

Similar/Related Questions

As a loop of wire with a resistance of 10 Ω moves in a constant non-uniform magnetic field, it loses kinetic energy at a uniform rate of 5.0 mJ/s. The induced current in the loop is: 0 A 2.0 mA 2.8 mA 22 mA cannot be calculated from the given data
Solution
0 0

a. A conducting bar is bent into a U-shape as shown below, with a sliding conductor placed across it. The sliding conductor moves at a constant velocity v→ = 100 ms in the presence of a time-varying magnetic field, B→ = a^z0.05 sin⁡(1000πt) T. If d = 0.5 m, determine the total emf developed in the loop at t = 3.25 ms. In what direction would current be at this time? Answer: Vemf = +19.8 V, current is CCW b. A square loop of wire is 25 cm on each side and has a resistance of 125 Ω/m. The loop lies in the z = 0 plane with its corners at (0, 0, 0), (0.25, 0, 0), (0.25, 0.25, 0), and (0, 0.25, 0) at t = 0. The loop is moving with velocity vy = 50 m/s in a B-field given by B→ = a^z8 cos⁡(1.5×108t − 0.5x) μT. Determine a function of time which expresses the ohmic power being delivered to the loop and then evaluate the expression at t = 5.00145281 ms. Answer: 20.9 W

Solution
0 0

Consider the conductive rod connected to a u-shaped loop of wire, shown below in Figure (a). The rod moves with a constant speed of 3.2 m/s in a 0.45 T magnetic field, and the rod has a length of I = 40 cm. If the rod has a resistance of 2.0 Ω (and resistance in the wires is negligible), how much electric energy will be produced in 0.5 seconds? Enter your solution in Joules.
Solution
0 0