Question

Notify Me Bookmark

As shown in the figure, a small particle of charge q = 7.0×10−9 C and mass m = 4×10−12 kg has velocity v0 = 9×103 m/s as it enters a region of uniform magnetic field. The particle is observed to travel in the semicircular path shown, with radius R = 5.0 cm. Calculate the magnitude and direction of the magnetic field in the region.

As shown in the figure, a small particle of charge q = 7.0×10−9 C and mass m = 4×10−12 kg has velocity v0 = 9×103 m/s as it enters a region of uniform magnetic field. The particle is observed to travel in the semicircular path shown, with radius R = 5.0 cm. Calculate the magnitude and direction of the magnetic field in the region.

Image text
As shown in the figure, a small particle of charge q = 7.0 × 10 − 9 C and mass m = 4 × 10 − 12 k g has velocity v 0 = 9 × 10 3 m / s as it enters a region of uniform magnetic field. The particle is observed to travel in the semicircular path shown, with radius R = 5.0 c m . Calculate the magnitude and direction of the magnetic field in the region.

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

A particle of charge q = 4.4×10−6 C and mass m = 2.1×10−6 kg moving at some initial velocity v→0 enters a region in which a uniform magnetic field B→ = 0.44 Tj is suddenly switched on. The particle then moves in a helix of radius r = 17 cm and pitch p = 10.7 cm about the y-axis, as shown in the figure. Assuming that the position of the particle when the magnetic field is switched on is (17 cm, 0 cm, 0 cm), express the initial velocity vector using ijk unit vector notation. v→0 = m/s
Solution
0 0

An ion with a mass m and a magnitude of charge of 1 e is initially at rest when it is accelerated by a potential difference of magnitude ΔV. After exiting the accelerating potential, it enters a region with a uniform magnetic field perpendicular to the ion's velocity. The ion moves in a semicircle of radius R. Next, an ion with a mass m′ and a magnitude of charge of 4e is accelerated by the same potential difference and deflected by the same magnetic field. The radius of its semicircular path is R′ = 3R. Find the ratio of the ion masses, m′/m. m′/m =
Solution
0 0

A positively charged particle of mass m and charge q is released from rest in a uniform electric field, E→ = (10i^) V/m. The particle, after travelling 2 s in this electric field, enters a region that is free from electric field but has a steady and uniform magnetic field, B→ = (−4k^) T. What will be the radius of the circular path (in meters) and the direction of angular velocity of the particle in this region? (Select the closest number among the following choices.) (Note: an incorrect answer will be penalized 2 pts.) a) 5.0; k^ b) 0.2; k^ c) 0.2; −k^ d) 2.0; k^ e) 5.0; −k^
Solution
0 0