Consider the diagram of the two charges shown below. The charge qA = -1.50 x 10−8 C. The charge qB = 2.00×10−8 C. The distance x = 1.50 m and the distance y = 2.60 m. What is the electric field due to the charges at point P. Fields to the right are considered positive and fields to the left are considered negative. If the field is to the left include a negative sign in your answer. If the field is to the right do NOT include the positive sign in your answer. You field should be given in N/C to 1 decimal place. Do NOT include units in your answer.