Question

Notify Me Bookmark

Example 23.5 Electric Field due to Two Charges Problem A charge q1 = 3.3 μC is located at the origin and a second charge q2 = −3.0 μC is located at the x axis, 0.30 m from the origin (Figure 23.14). Find the electric field at the point P, which has coordinates (0, 0.40)m. Figure 23.14 The total electric field E at P equals the vector sum E1 + E2, where E1 is the field due to the positive charge q1 and E2 is the negative charge q2

Example 23.5 Electric Field due to Two Charges Problem A charge q1 = 3.3 μC is located at the origin and a second charge q2 = −3.0 μC is located at the x axis, 0.30 m from the origin (Figure 23.14). Find the electric field at the point P, which has coordinates (0, 0.40)m. Figure 23.14 The total electric field E at P equals the vector sum E1 + E2, where E1 is the field due to the positive charge q1 and E2 is the negative charge q2

Image text
Example 23.5 Electric Field due to Two Charges Problem A charge q 1 = 3.3 μ C is located at the origin and a second charge q 2 = − 3.0 μ C is located at the x axis, 0.30 m from the origin (Figure 23.14). Find the electric field at the point P , which has coordinates ( 0 , 0.40 ) m . Figure 23.14 The total electric field E at P equals the vector sum E 1 + E 2 , where E 1 is the field due to the positive charge q 1 and E 2 is the negative charge q 2

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

Two charged point-like objects are located on the x-axis. The point-like object with charge q1 = 6.00 μC is located at x1 = 1.25 cm and the point-like object with charge q2 = −2.40 μC is located at x2 = −1.80 cm (a) Determine the total electric potential (in V ) at the origin. V (b) Determine the total electric potential (in V ) at the point with coordinates (0, 1.50 cm). V
Solution
0 0

A point charge q1 = 4.10 nC is located at the x-axis at x = 2.00 m, and a second point charge q2 = −6.30 nC is on the y-axis at y = 1.00 m. What is the total electric flux due to these two point charges through a spherical surface centered at the origin and with the following radius? (a) 0.500 m N⋅m2 /C (b) 1.50 m N⋅m2 /C (c) 2.50 m N⋅m2 /C
Solution
0 0

In the figure shown below, three charges are places at the corners of a rectangle. Charges q1 and q2 are located in the upper left and right corners, respectively and charge q3 is places in the lower left corner. The separation distance of q1 and q3 is the distance a. The lower right corner, which does not contain a charge, is labeled as point P1. A second point, P2, is on the top side of the rectangle, a distance b from charge q1 and c from charge q2. For this question, let q1 = 58.00000 nC, q2 = −12.00000 nC, q3 = −20.00000 nC, a = 12.00000 cm, b = 16.00000 cm and c = 6.00000 cm. (If you wish to get correct answers, then be sure to use ke = 9.00000×109 N⋅m2 /C2 and e = 1.60000×10−19 C.) The angle of the electric field at point P2 due only to q3, as measured from the positive x-axis, in degrees and to three decimal places, is
Solution
0 0