For block A (mass 2.5 kg) resting on a tabletop and block B (mass 1.5 kg) hanging from a cord over a frictionless pulley, with a coefficient of kinetic friction of 0.35 between block A and the tabletop: a. Draw the free-body diagrams for blocks A and B. b. Derive the equation for the constant acceleration of the system based on Newton's second law. c. Calculate the constant acceleration of the system and the tension in the cord. A B
![Two blocks A and B with masses mA = 10 kg and mB = 4 kg are connected by an inextensible cable and released from rest shown in Figure 1 (where block A is placed in position C ). The coefficients of kinetic friction between two blocks and the 30∘ inclined plane are μA = 0.1 and mB = 0.3. The cable is in tension in the entire motion and the sizes of blocks are negligible. (Take gravitational acceleration as 10 m/s2) (a) Draw separate free body diagrams of blocks A and B. Indicate clearly all the forces, directions of motion and coordinate systems. [4 marks] b) Based on the free body diagrams in part (a), establish the equations of motion for blocks A and B and determine the tension in the cable between two blocks. [12 marks] (c) Determine the time required for block A to move 2.5 m from positions C to D along the incline and the velocity of block A when it reaches position D. [4 marks] Figure 1](https://www.doubtrix.com/uploads/editor/3466504776qCVzpwjiZa.png)
