Question

Notify Me Bookmark

In a plot of current versus potential difference, which feature characterizes a device that obeys Ohm's law? The plot is symmetric about the vertical axis. The slope is zero. The plot is curved, with a constant positive curvature. The plot is curved, with a constant negative curvature. The slope is constant.

In a plot of current versus potential difference, which feature characterizes a device that obeys Ohm's law? The plot is symmetric about the vertical axis. The slope is zero. The plot is curved, with a constant positive curvature. The plot is curved, with a constant negative curvature. The slope is constant.

Image text
In a plot of current versus potential difference, which feature characterizes a device that obeys Ohm's law? The plot is symmetric about the vertical axis. The slope is zero. The plot is curved, with a constant positive curvature. The plot is curved, with a constant negative curvature. The slope is constant.

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

A solid conducting sphere of radius a is held at a constant potential V0 which is not necessarily zero. It is surrounded by a thin concentric spherical shell of radius b, as shown in Figure 1 , on which a surface charge density exists, given by σ(θ) = k cosθ where k is a constant and θ is the polar angle in spherical coordinates. The regions in-between the conductor and the shell, and outside the shell, are vacuum. Figure 1 (a) State the boundary conditions on the potential and its radial derivative at r = b. (b) You are given the general solution to Laplace’s equation with azimuthal symmetry, in the two regions, as follows: V(r,θ) = (P l Alr l + Bl r l+1 Pl(cos θ), for r ≥ b P l Clr l + Dl r l+1 Pl(cos θ), for a ≤ r ≤ b Determine the coefficients Al , Bl , Cl and Dl for all l. (c) Hence, show that the induced surface charge density on the inner conductor is given by σi(θ) = -kcosθ + V0 ϵ0/a The first two Legendre polynomials are given for this question: P0(x) = 1, P1(x) = x.
Solution
0 0

The figure here shows a plot of potential energy U versus position x of a 0.852 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) Three values are UA = 15.0 J, UB = 35.0 J and UC = 45.0 J. The particle is released at x = 4.50 m with an initial speed of 7.89 m/s, headed in the negative x direction. (a) If the particle can reach x = 1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to move to the left of x = 4.00 m ? Suppose, instead, the particle is headed in the positive x direction when it is released at x = 4.50 m at speed 7.89 m/s. (d) If the particle can reach x = 7.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (e) magnitude and (f) direction of the force on the particle as it begins to move to the right of x = 5.00 m?
Solution
0 0

The figure here shows a plot of potential energy U versus position x of a 0.884 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) Three values are UA = 15.0 J, UB = 35.0 J and UC = 45.0 J. The particle is released at x = 4.50 m with an initial speed of 7.82 m/s, headed in the negative x direction. (a) If the particle can reach x = 1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to move to the left of x = 4.00 m? Suppose, instead, the particle is headed in the positive x direction when it is released at x = 4.50 m at speed 7.82 m/s. (d) If the particle can reach x = 7.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (e) magnitude and (f) direction of the force on the particle as it begins to move to the right of x = 5.00 m? (a) Number Unit (b) Number Unit (c) (d) Number Unit (e) Number Unit (f)
Solution
0 0