In the figure, a horizontal scaffold, of length 2.86 m and uniform mass 52.6 kg, is suspended from a building by two cables. The scaffold has dozens of paint cans stacked on it at various points. The total mass of the paint cans in 74.8 kg. The tension in the cable at the right is 798 N. How far horizontally from that cable is the center of mass of the system of paint cans?
![A horizontal underwater plastic meter stick, of mass 407 g and volume 3× 10−4 m3, has two additional forces acting on it. There is a downward force of 2 N applied to the left end of the stick and a 6 N force to the right acting on the extreme right end of the stick. [Hint: The buoyant force on a symmetric body of uniform density acts at the geometric center of the body.] Assume g ≈ 10 N/kg. (a) If we want to suspend the stick from a single cable, how far from the left end of the stick must the force be applied? r = m ( ± 0.01 m) (b) What will be the tension in the cable? T = N ( ± 0.02 N) (c) What angle will the cable make with the vertical? θ = ∘( ± 0.1∘)](https://www.doubtrix.com/uploads/editor/9027192268ugZTcncBjz.png)
