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In the figure, an electron moves at speed v = 58.8 m/s along an x axis through uniform electric and magnetic fields without accelerating. The magnetic field B→ is directed into the page and has magnitude 4.88 T. In unit-vector notation, what is the electric field? Number Units

In the figure, an electron moves at speed v = 58.8 m/s along an x axis through uniform electric and magnetic fields without accelerating. The magnetic field B→ is directed into the page and has magnitude 4.88 T. In unit-vector notation, what is the electric field? Number Units

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In the figure, an electron moves at speed v = 58.8 m / s along an x axis through uniform electric and magnetic fields without accelerating. The magnetic field B → is directed into the page and has magnitude 4.88 T. In unit-vector notation, what is the electric field?
Number ◻ ◻ r ˙ + j + ◻ k ) Units

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In the figure, an electron moves at speed v = 58.8 m/s along an x axis through uniform electric and magnetic fields without accelerating. The magnetic field B→ is directed into the page and has magnitude 4.88 T. In unit-vector notation, what is the electric field? Number Units
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In the figure (Figure 1) a conducting rod of length L = 30.0 cm moves in a magnetic field B→ of magnitude 0.490 T directed into the plane of the figure. The rod moves with speed v = 5.90 m/s in the direction shown. Figure 1 of 1 Part A What is the potential difference between the ends of the rod? Express your answer in volts. V = Submit Request Answer Part B Which point, a or b, is at higher potential? a b Part C When the charges in the rod are in equilibrium, what is the magnitude of the electric field within the rod? Express your answer in volts per meter. Submit Request Answer Part D What is the direction of the electric field within the rod? From b to a From a to b Part E When the charges in the rod are in equilibrium, which point, a or b, has an excess of positive charge? a b Submit Request Answer Part F What is the potential difference across the rod if it moves parallel to ab ? Express your answer in volts. 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