Question

Notify Me Bookmark

Nine identical wires, each of diameter d and length L, are connected in series. The combination has the same resistance as a single similar wire of length L but whose diameter is: 9 d 3 d d/3 d/9 d/81

Nine identical wires, each of diameter d and length L, are connected in series. The combination has the same resistance as a single similar wire of length L but whose diameter is: 9 d 3 d d/3 d/9 d/81

Image text
Nine identical wires, each of diameter d and length L , are connected in series. The combination has the same resistance as a single similar wire of length L but whose diameter is: 9 d 3 d d / 3 d / 9 d / 81

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

You just landed a job as an assistant to an electrician who is working on a building site. He is making use of long single-conductor insulated wire for some of the connections in the complicated "smart building." A new shipment of spools of this wire has been delivered, and the electrician is not happy that it came from a manufacturer that he suspects is producing inferior wire. The electrician asks you to determine the resistance per unit length of the wire (in Ω/m ) and provides you with a battery and a high-quality multimeter. Despite the quality of the meter, he suggests that you not use the ohmmeter to measure resistance, because the value of the resistance is so low that the meter is not likely to measure it accurately. You are puzzled as to how to go about this task. As the electrician runs off to attend to another task, he says, "Cut off a couple of different lengths of wire and use the battery and the multimeter. " You put the multimeter in voltage mode across the terminals of the battery without a wire connected and measure 7.00 V. You then cut off two lengths of wire, one 5.00 m in length, and one 10.0 m in length. Connecting them one at a time to the battery through the multimeter in current mode, you find that there is a current of 5.17 A in the 5.00 m length of wire, and 3.00 A in the 10.0 m length of wire. Ah-ha, now you have enough information! Ω/m
Solution
0 0

Both drawings show the same square, each of which has a side of length L = 0.76 m. An observer O is stationed at one corner of each square. Two loudspeakers are located at corners of the square, as in either drawing 1 or drawing 2. The speakers produce the same single-frequency tone in either drawing and are in phase. The speed of sound is 343 m/s. Find the single smallest frequency that will produce both constructive interference in drawing 1 and destructive interference in drawing 2. f =
Solution
0 0

Consider the CMOS inverter, connected in resistive feedback, shown below. Model the transistors as having square-law behavior, such that ID1 = knW1/L1( VGS - VTHn)2(1+lambda*VDS) and ID2=kpW2/L2( VGS-VTHp)2(1+lambda*VDS). Also assume: kn=3kp, VTHN=-VTHP =VDD/3, that the devices have the same value of ? and that the nmos bulk is grounded, and pmos bulk is to VDD. Also assume the circuit is biased so that if Vin =Vin0+?Vin then when Vin =Vin0, Vout =Vin . Draw the complete small-signal model of this amplifier, showing each transistor's elements explicitly, assuming M1 and M2 are in saturation. Then, redraw a simplified small signal model (collapsing parallel resistances, capacitances and transconductances into single components and eliminating zero-value components), in this simplified model, also apply Millers' theorem to break RF into resistors to ground on input and output (leave voltage gain as an unknown variable Av ).
Solution
3 0