Question

Notify Me Bookmark

One end of a M = 0.1 kg meter stick is attached to a wall, and provided with a pivot. A vertical force F is applied to the other end to make the net torque about the pivot point zero. What is the magnitude of F and the direction of the torque produced by F. F = 0.5 N, torque = 0.5 Nm into the page. F = 0.1 N, torque = 0.1 Nm out of page. F = 0.5 N, torque = 0.5 Nm out of page. F = 0.1 N, torque = 0.2 Nm out of page. F = 1 N, torque = 1 Nm upward.

One end of a M = 0.1 kg meter stick is attached to a wall, and provided with a pivot. A vertical force F is applied to the other end to make the net torque about the pivot point zero. What is the magnitude of F and the direction of the torque produced by F. F = 0.5 N, torque = 0.5 Nm into the page. F = 0.1 N, torque = 0.1 Nm out of page. F = 0.5 N, torque = 0.5 Nm out of page. F = 0.1 N, torque = 0.2 Nm out of page. F = 1 N, torque = 1 Nm upward.

Image text
One end of a M = 0.1 k g meter stick is attached to a wall, and provided with a pivot. A vertical force F is applied to the other end to make the net torque about the pivot point zero. What is the magnitude of F and the direction of the torque produced by F . F = 0.5 N , torque = 0.5 N m into the page. F = 0.1 N , torque = 0.1 N m out of page. F = 0.5 N , torque = 0.5 N m out of page. F = 0.1 N , torque = 0.2 N m out of page. F = 1 N , torque = 1 N m upward.

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

A simple pendulum consists of a small ball of mass m = 193 g swinging on a massless, inextensible string of length R = 7 m. At time t = 0 the pendulum is released from the horizontal position, as shown below. A short time later, the pendulum reaches the bottom of its swing and encounters a nail sticking out of the page a distance L = 5.7 m below the pivot point. The pendulum begins to wrap around the nail, and at time t = ttop it is at the top of its first rotation. (e) Find the magnitude and direction of the net force on the ball at t = ttop. ΣF = N (±0.2 N) (f) Find the tension in the string at t = ttop. T = N (±0.2 N)A simple pendulum consists of a small ball of mass m = 193 g swinging on a massless, inextensible string of length R = 7 m. At time t = 0 the pendulum is released from the horizontal position, as shown below. A short time later, the pendulum reaches the bottom of its swing and encounters a nail sticking out of the page a distance L = 5.7 m below the pivot point. The pendulum begins to wrap around the nail, and at time t = ttop it is at the top of its first rotation. (e) Find the magnitude and direction of the net force on the ball at t = ttop. ΣF = N (±0.2 N) (f) Find the tension in the string at t = ttop. T = N (±0.2 N)A simple pendulum consists of a small ball of mass m = 193 g swinging on a massless, inextensible string of length R = 7 m. At time t = 0 the pendulum is released from the horizontal position, as shown below. A short time later, the pendulum reaches the bottom of its swing and encounters a nail sticking out of the page a distance L = 5.7 m below the pivot point. The pendulum begins to wrap around the nail, and at time t = ttop it is at the top of its first rotation. (e) Find the magnitude and direction of the net force on the ball at t = ttop. ΣF = N (±0.2 N) (f) Find the tension in the string at t = ttop. T = N (±0.2 N)
Solution
0 0

Two regions of a mass spectrometer are shown below. In the velocity selector region, the ions are focused into a beam with a single speed in the direction shown using an electric field of 500 V/m and magnetic field |B→1| = 0.5 T perpendicular to one another. In the region to the right, a single magnetic field, B→2 is used to deflect the particles in a circular path which land at the detector. In this region, electrons experience a force of 1.0×10−16 N and move in the circular path shown. What is the strength and direction of the magnetic field, B→2? Ignore gravity. 0.63 T out of the page 1.6 T out of the page 0.63 T into the page 630000 T out of the page 1.6 T into the page
Solution
0 0

Three forces are applied to a wheel of radius 0.350 m, as shown in the figure (Figure 1). One force is perpendicular to the rim, one is tangent to it, and the other one makes a 40.0∘ angle with the radius. Figure 1 of 1 Part A What is the magnitude of the net torque on the wheel due to these three forces for an axis perpendicular to the wheel and passing through its center? Express your answer in newton-meters. τ = N⋅m Submit Request Answer Part B What is the direction of the net torque in part (A)? into the page out of the page Submit Request Answer Three forces are applied to a wheel of radius 0.350 m, as shown in the figure (Figure 1). One force is perpendicular to the rim, one is tangent to it, and the other one makes a 40.0∘ angle with the radius. Figure 1 of 1 Part A What is the magnitude of the net torque on the wheel due to these three forces for an axis perpendicular to the wheel and passing through its center? Express your answer in newton-meters. τ = N⋅m Submit Request Answer Part B What is the direction of the net torque in part (A)? into the page out of the page Submit Request Answer

Solution
0 0