P55. A fish swimming in a horizontal plane has velocity vi = 2 i+6 j/s at a point in the ocean where the position relative to a certain rock is ri = −6i + 4j m. After the fish swims with constant acceleration for 13 s, its velocity is v = −2i + 2j m/s. If the fish maintains constant acceleration, what is its horizontal position at t = 33 s? (-107.53846153846 m)