The acceleration of a particle is given by ax(t) = −2.10 m/s2 + (2.98 m/s3)t Part A Find the initial velocity v0x such that the particle will have the same x-coordinate at time t = 4.02 s as it had at t = 0. Express your answer in meters per second. v0x = m/s Submit Request Answer Part B What will be the velocity at time t = 4.02 s? Express your answer in meters per second. Submit Request Answer