The acceleration of a particle moving only on a horizontal xy plane is given by a→ = 5ti^ + 6tj^, where a→ is in meters per second-squared and t is in seconds. At t = 0, the position vector r→ = (27.0 m)i^ + (36.0 m)j^ locates the particle, which then has the velocity vector v→ = (7.40 m/s)i^ + (2.20 m/s)j^. At t = 2.80 s, what are (a) its position vector in unit-vector notation and (b) the angle between its direction of travel and the positive direction of the x axis? (a) Number i^ + j^ Units (b) Number Units