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The angle (with respect to the vertical) of a simple pendulum is given by θ = θmcos⁡[(5.88 rad/s)t + ϕ]. If at t = 0, θ = 0.0450 rad and dθ/dt = −0.160 rad/s, what are (a) the phase constant ϕ and (b) the maximum angle θm ? (Hint: Don't confuse the rate dθ/dt at which θ changes with the ω of the SHM.) (a) Number Unit (b) Number Unit

The angle (with respect to the vertical) of a simple pendulum is given by θ = θmcos⁡[(5.88 rad/s)t + ϕ]. If at t = 0, θ = 0.0450 rad and dθ/dt = −0.160 rad/s, what are (a) the phase constant ϕ and (b) the maximum angle θm ? (Hint: Don't confuse the rate dθ/dt at which θ changes with the ω of the SHM.) (a) Number Unit (b) Number Unit

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The angle (with respect to the vertical) of a simple pendulum is given by θ = θ m cos ⁡ [ ( 5.88 r a d / s ) t + ϕ ] . If at t = 0 , θ = 0.0450 r a d and d θ / d t = − 0.160 r a d / s , what are (a) the phase constant ϕ and (b) the maximum angle θ m ? (Hint: Don't confuse the rate d θ / d t at which θ changes with the ω of the SHM.) (a) (b) (a) Number i Unit ◻ (b) Number i Unit ◻

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