Question

Notify Me Bookmark

The dipole moment of a dipole in a 300-N/C electric field is initially perpendicular to the field, but it rotates so it is in the same direction as the field. If the moment has a magnitude of 2×10−9 C⋅m the work done by the field is: −12×10−7 J −6×10−7 J 0 J 6×10−7 J 12×10−7 J

The dipole moment of a dipole in a 300-N/C electric field is initially perpendicular to the field, but it rotates so it is in the same direction as the field. If the moment has a magnitude of 2×10−9 C⋅m the work done by the field is: −12×10−7 J −6×10−7 J 0 J 6×10−7 J 12×10−7 J

Image text
The dipole moment of a dipole in a 300-N/C electric field is initially perpendicular to the field, but it rotates so it is in the same direction as the field. If the moment has a magnitude of 2 × 10 − 9 C ⋅ m the work done by the field is: − 12 × 10 − 7 J − 6 × 10 − 7 J 0 J 6 × 10 − 7 J 12 × 10 − 7 J

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after traveling a distance d. (a) What is the magnitude of the electric field? (Use any variable or symbol stated above along with the following as necessary: e for the charge of the electron.) E = (b) What is the direction of the electric field? in the direction of the electron's motion opposite to the direction of the electron's motion perpendicular to the direction of the electron's motion (c) What If? Fluoride ions (which have the same charge as an electron) are initially moving with the same speed as the electrons from part (a) through a different uniform electric field. The ions come to a stop in the same distance d. Let the mass of an ion be M and the mass of an electron be m. Find the ratio of the magnitude of electric field the ions travel through to the magnitude of the electric field found in part (a). (Use the following as necessary: d, k, m, M, and e for the charge of the electron.) Enew Epart (a) =
Solution
0 0

An ion with a mass m and a magnitude of charge of 1 e is initially at rest when it is accelerated by a potential difference of magnitude ΔV. After exiting the accelerating potential, it enters a region with a uniform magnetic field perpendicular to the ion's velocity. The ion moves in a semicircle of radius R. Next, an ion with a mass m′ and a magnitude of charge of 4e is accelerated by the same potential difference and deflected by the same magnetic field. The radius of its semicircular path is R′ = 3R. Find the ratio of the ion masses, m′/m. m′/m =
Solution
0 0

The figure gives the potential energy U of a magnetic dipole in an external magnetic field B→, as a function of angle φ between the directions of B→ and the dipole moment. The vertical axis scale is set by Us = 1.9×10−4 J. The dipole can be rotated about an axle with negligible friction so as to change φ. Counterclockwise rotation from φ = 0 yields positive values of φ, and clockwise rotations yield negative values. The dipole is to be released at angle φ = 0 with a rotational kinetic energy of 5.9×10−4 J, so that it rotates counterclockwise. To what maximum value of φ will it rotate? Number Units
Solution
0 0