Question

Notify Me Bookmark

The figure shows an overhead view of a 0.0210 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force F→1 has a magnitude of 3.00 N and is at θ1 = 27.0∘. Force F→2 has a magnitude of 6.00 N and is at θ2 = 31.0∘. In unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity v→ = (12.0i^ − 13.0j^) m/s, and (c) has the varying velocity v→ = (11.0ti^ − 12.0tj^) m/s, where t is time?

The figure shows an overhead view of a 0.0210 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force F→1 has a magnitude of 3.00 N and is at θ1 = 27.0∘. Force F→2 has a magnitude of 6.00 N and is at θ2 = 31.0∘. In unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity v→ = (12.0i^ − 13.0j^) m/s, and (c) has the varying velocity v→ = (11.0ti^ − 12.0tj^) m/s, where t is time?

Image text
The figure shows an overhead view of a 0.0210 k g lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force F → 1 has a magnitude of 3.00 N and is at θ 1 = 27.0 ∘ . Force F → 2 has a magnitude of 6.00 N and is at θ 2 = 31.0 ∘ . In unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity v → = ( 12.0 i ^ − 13.0 j ^ ) m / s , and (c) has the varying velocity v → = ( 11.0 t i ^ − 12.0 t j ^ ) m / s , where t is time?

Detailed Answer

3 0

Please enter your email here. You will get email when this question is answered by our tutor.

Answer
Doubtrix Logo

This Problem has been solved!

You'll get a detailed, step-by-step and expert verified solution.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Login Sign Up
  • Student Reviews:
  • (3)
  • Correct answers (3)
  • Complete solution (3)
  • Step-by-step solution (3)
  • Fully explained (3)

Similar/Related Questions

The figure shows an overhead view of a 0.021 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force F→1 has a magnitude of 4 N and is at θ1 = 28∘. Force F→ has a magnitude of 7 N and is at θ2 = 26∘. In unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity v→ = (10i^ − 16j^)m/s, and (c) has the v→ = (10i^ − 14tj^) m/s2, where t is time? (a) Number i+ j Units (b) Number i+ j Units (c) Number i+ j Units
Solution
1 0

Two forces are applied on a 2.00 kg box to move it. In the overhead view of the system, one force has a magnitude of 20.0 N and is applied along the +x axis. This results in an acceleration of the box of magnitude 12.0 m/s2 in the direction given by the angle θ = 30∘ as shown in the diagram below. (a) Determine the magnitude of the second force. (b) Determine the direction of the second force. After a while, a third force is applied on the box and as a result it now moves with a constant velocity. (c) What is the magnitude of the third force? (d) What is the direction of the third force? (e) Draw all three forces in the overhead view of the box.
Solution
0 0

The figure here shows an overhead view of three horizontal forces acting on a cargo canister that was initially stationary but that now moves across a frictionless floor. The force magnitudes are F1 = 2.80 N. F2 = 3.90 N and F3 = 10.0 N, and the indicated angles are θ2 = 48.0∘ and θ3 = 34.0∘. What is the net work done on the canister by the three forces during the first 4.30 m of displacement? Number Unit
Solution
0 0