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The figure shows wire section 1 of diameter D1 = 5.50R and wire section 2 of diameter D2 = 4.00R, connected by a tapered section. The wire is copper and carries a current. Assume that the current is uniformly distributed across any cross-sectional area through the wire's width. The electric potential change V along the length L = 1.70 m shown in section 2 is 15.0 μV. The number of charge carriers per unit volume is 8.70×1028 m−3. What is the drift speed of the conduction electrons in section 1? Number Units

The figure shows wire section 1 of diameter D1 = 5.50R and wire section 2 of diameter D2 = 4.00R, connected by a tapered section. The wire is copper and carries a current. Assume that the current is uniformly distributed across any cross-sectional area through the wire's width. The electric potential change V along the length L = 1.70 m shown in section 2 is 15.0 μV. The number of charge carriers per unit volume is 8.70×1028 m−3. What is the drift speed of the conduction electrons in section 1? Number Units

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The figure shows wire section 1 of diameter D 1 = 5.50 R and wire section 2 of diameter D 2 = 4.00 R , connected by a tapered section. The wire is copper and carries a current. Assume that the current is uniformly distributed across any cross-sectional area through the wire's width. The electric potential change V along the length L = 1.70 m shown in section 2 is 15.0 μ V . The number of charge carriers per unit volume is 8.70 × 10 28 m − 3 . What is the drift speed of the conduction electrons in section 1 ? (1) (2) ( 1 )
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