The index of refraction for violet light in silica flint glass is 1.66

Question

Notify Me Bookmark

The index of refraction for violet light in silica flint glass is 1.66 and that for red light is 1.62. What is the angular dispersion of visible light passing through an equilateral prism of apex angle 60.0∘ if the angle of incidence is 45.0∘? (See figure. The index of refraction for air is 1.00.)

$The index of refraction for violet light in silica flint glass is 1.66 and that for red light is 1.62. What is the angular dispersion of visible light passing through an equilateral prism of apex angle 60.0∘ if the angle of incidence is 45.0∘? (See figure. The index of refraction for air is 1.00.)$

Image text

The index of refraction for violet light in silica flint glass is 1.66 and that for red light is 1.62 . What is the angular dispersion of visible light passing through an equilateral prism of apex angle

{60.0}^{\circ}

if the angle of incidence is

{45.0}^{\circ}

? (See figure. The index of refraction for air is 1.00.)

◻

Detailed Answer

Ask Your Doubt Rate This Answer Request Video Solution

Previous question

Next question

Submit Questions

Similar/Related Questions

$Assume that two waves of light in air, of wavelength 480. nm, are initially π rad out of phase. One travels through a glass layer of index of refraction n1 = 1.45 and thickness L. The other travels through an equally thick plastic layer of index of refraction n2 = 1.65. What is the smallest value of L so that the waves end up exactly in phase once they pass through the two media? 1.20 × 103 nm 300 nm 480 nm 1.80 × 103 nm 960 nm$

Solution

$A glass cover is placed over a water drop on a glass slide. When this is done, orange light (λ = 605 nm in air) is reflected particularly strongly. What is the minimum possible thickness (nm) of water between the cover and slide? The index of refraction of the glass (cover and slide) is 1.54 and is 1.33 for water. The slide is too thick to be a thin film, just consider the water sandwiched between the cover and slide to be the film. 199 227 398 151 369 114 455 512 302 284$

Solution

$In the figure, a light ray in air is incident on a flat layer of material 2 that has an index of refraction n2 = 4.4. Beneath material 2 is material 3 with an index of refraction n3. The ray is incident on the air-material 2 interface at the Brewster angle for that interface. The ray of light refracted into material 3 happens to be incident on the material 2-material 3 interface at the Brewster angle for that interface. What is the value of n3? Number Units$

Solution