Question

Notify Me Bookmark

The International Space Station makes 15.65 revolutions per day in its orbit around the earth. Part A Assuming a circular orbit, how high is this satellite above the surface of the earth? Express your answer in kilometers to three significant figures. h = km

The International Space Station makes 15.65 revolutions per day in its orbit around the earth. Part A Assuming a circular orbit, how high is this satellite above the surface of the earth? Express your answer in kilometers to three significant figures. h = km

Image text
The International Space Station makes 15.65 revolutions per day in its orbit around the earth. Part A Assuming a circular orbit, how high is this satellite above the surface of the earth? Express your answer in kilometers to three significant figures.
h = ◻ k m

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

The 20-lb block B rests on the surface of a table shown in (Figure 1) for which the coefficient of kinetic friction is μk = 0.11. Assume WC = 6 lb. Figure 1 of 1 Part A Determine the speed of the 10-lb block A after it has moved downward 2 ft from rest. Neglect the mass of the pulleys and cords. Express your answer in feet per second to three significant figures. vA = ft/s? Submit Previous Answers Request Answer
Solution
3 0

The radius of the earth's orbit around the sun (assumed to be circular) is 1.50×108 km, and the earth travels around this orbit in 365 days. Part A What is the magnitude of the orbital velocity of the earth in m/s ? Express your answer in meters per second. Part B What is the radial acceleration of the earth toward the sun? Express your answer in meters per second squared. Submit Request Answer Part C What is the magnitude of the orbital velocity of the planet Mercury (orbit radius = 5.79×107 km, orbital period = 88.0 days )? Express your answer in meters per second.The radius of the earth's orbit around the sun (assumed to be circular) is 1.50×108 km, and the earth travels around this orbit in 365 days. Part A What is the magnitude of the orbital velocity of the earth in m/s ? Express your answer in meters per second. Part B What is the radial acceleration of the earth toward the sun? Express your answer in meters per second squared. Submit Request Answer Part C What is the magnitude of the orbital velocity of the planet Mercury (orbit radius = 5.79×107 km, orbital period = 88.0 days )? Express your answer in meters per second.
Solution
0 0

Part A Find the position of the center of mass of the system of the sun (1.99×1030 kg) and Jupiter (1.90×1027 kg). The orbit radius of Jupiter is 7.78×1011 m. (Since Jupiter is more massive than the rest of the planets combined, this is essentially the position of the center of mass of the solar system. ) Express your answer in meters to three significant figures. x = m from the center of the sun Submit Request Answer Part B Does the center of mass lie inside or outside the sun? The sun's radius is 6.96×108 m. inside outside

Solution
0 0