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The kid from last time is pulling the sled with mass m kg by a massless, taut string with constant tension T N at the angle θ shown. The pull is not large enough to lift the sled off the snow, and the block has initial velocity v0 m/s. There is friction with the coefficient μk between the block and the surface. After the block is pulled through a horizontal distance Lm, what is the change in velocity Δv = vf − v0? m = 1.7 T = 11 θ = 20∘ v0 = 1.1 μk = 0.26 L = 7 Find change in velocity Δv = Type your numeric answer and submit

The kid from last time is pulling the sled with mass m kg by a massless, taut string with constant tension T N at the angle θ shown. The pull is not large enough to lift the sled off the snow, and the block has initial velocity v0 m/s. There is friction with the coefficient μk between the block and the surface. After the block is pulled through a horizontal distance Lm, what is the change in velocity Δv = vf − v0? m = 1.7 T = 11 θ = 20∘ v0 = 1.1 μk = 0.26 L = 7 Find change in velocity Δv = Type your numeric answer and submit

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The kid from last time is pulling the sled with mass m k g by a massless, taut string with constant tension T N at the angle θ shown. The pull is not large enough to lift the sled off the snow, and the block has initial velocity v 0 m / s . There is friction with the coefficient μ k between the block and the surface. After the block is pulled through a horizontal distance L m , what is the change in velocity Δ v = v f − v 0 ?
m = 1.7 T = 11 θ = 20 ∘ v 0 = 1.1 μ k = 0.26 L = 7
Find change in velocity Δ v = Type your numeric answer and submit

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