Question

Notify Me Bookmark

The potential energy (in Joules) of a particle of mass 9 kg is given by the function U(x) = 1500 − 70x2 + x4. The figure shows a plot of U(x) versus the particle position x. The particle can travel only along the x axis and is under the influence of a conservative force. The particle is released at 5 m with a speed of 11 m/s. (a) Determine the total mechanical energy of the particle. Etot = J

The potential energy (in Joules) of a particle of mass 9 kg is given by the function U(x) = 1500 − 70x2 + x4. The figure shows a plot of U(x) versus the particle position x. The particle can travel only along the x axis and is under the influence of a conservative force. The particle is released at 5 m with a speed of 11 m/s. (a) Determine the total mechanical energy of the particle. Etot = J

Image text
The potential energy (in Joules) of a particle of mass 9 k g is given by the function U ( x ) = 1500 − 70 x 2 + x 4 . The figure shows a plot of U ( x ) versus the particle position x . The particle can travel only along the x axis and is under the influence of a conservative force. The particle is released at 5 m with a speed of 11 m / s . (a) Deremine the total mechanical energy of the particle. E tex = ◻ J

Detailed Answer

0 0

Please enter your email here. You will get email when this question is answered by our tutor.

Doubtrix Logo

Problem is not yet solved!

Click on Notify me to get email when question is answered.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Notify me Login Sign Up

Similar/Related Questions

The potential energy (in Joules) of a particle of mass 9 kg is given by the function U(x) = 1500 − 70x2 + x4. The figure shows a plot of U(x) versus the particle position 2 . The particle can travel only along the x axis and is under the influence of a conservative force. The particle is released at 5 m with a speed of 11 m/s. (a) Determine the total mechanical energy of the particle. Etot = (b) What is the speed of the particle at x = 7 m? v = m/s (c) Determine the two turning points of the motion of the particle. Enter your answer such that x1 represents the turning point with larger numerical value (ie, x1 > x2 ). x1 = m x2 = m
Solution
0 0

The figure shows a plot of potential energy U versus position x of a 0.230 kg particle that can travel only along an x axis under the influence of a conservative force. The graph has these values: UA = 9.00 J, UC = 20.0 J and UD = 24.0 J. The particle is released at the point where U forms a "potential hill" of "height" UB = 12.0 J, with kinetic energy 7.00 J. What is the speed of the particle at (a)x = 3.50 m and (b)x = 6.50 m ? What is the position of the turning point on (c) the right side and (d) the left side?
Solution
0 0

The figure shows a plot of potential energy U versus position x of a 0.230 kg particle that can travel only along an x axis under the influence of a conservative force. The graph has these values: UA = 9.00 J, UC = 20.0 J and UD = 24.0 J. The particle is released at the point where U forms a "potential hill" of "height" UB = 12.0 J, with kinetic energy 6.00 J. What is the speed of the particle at (a)x = 3.50 m and (b)x = 6.50 m? What is the position of the turning point on (c) the right side and (d) the left side? (a) Number Units (b) Number Units (c) Number Units (d) Number Units
Solution
0 0