The speed of a car increases uniformly with time from 51 km/h at A to 103 km/h at B during 16 seconds. The radius of curvature of the hump at A is 36 m. If the magnitude of the total acceleration of the mass center of the car is the same at B as at A, compute the radius of curvature ρB of the dip in the road at B. The mass center of the car is 0.73 m from the road. Assume ρA = 36 m, h = 0.73 m. Answer: ρB = m