Question

Notify Me Bookmark

Three point charges are arranged on a line. Charge q3 = +5.00 nC and is at the origin. Charge q2 = -2.00 nC and is at x = 3.50 cm. Charge q1 is at x = 1.00 cm. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Vector addition of electric forces on a line. Part A What is q1 (magnitude and sign) if the net force on q3 is zero? Express your answer in nanocoulombs. Q1 = nC

Three point charges are arranged on a line. Charge q3 = +5.00 nC and is at the origin. Charge q2 = -2.00 nC and is at x = 3.50 cm. Charge q1 is at x = 1.00 cm. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Vector addition of electric forces on a line. Part A What is q1 (magnitude and sign) if the net force on q3 is zero? Express your answer in nanocoulombs. Q1 = nC

Image text
Three point charges are arranged on a line. Charge q3 = +5.00 nC and is at the origin. Charge q2 = -2.00 nC and is at x = 3.50 cm. Charge q1 is at x = 1.00 cm. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Vector addition of electric forces on a line. Part A What is q1 (magnitude and sign) if the net force on q3 is zero? Express your answer in nanocoulombs. Q1 = nC

Explanation & Steps

Force between two charges can be determined F = kQ1Q2/r^2. The force on Q2 due to Q1 will be towards Q1 if both are opposite charges and will be away of Q1 if both are same charge.

For the given question, the force on q3 due to q1 and q2 can be calculated. The direction of force between q1 and q3 must be opposite to the force direction between q1 and q3. Both forces can be used to determine exact location of the charge q1 on the x-axis.  

Detailed Answer

2 0

Please enter your email here. You will get email when this question is answered by our tutor.

Answer
Doubtrix Logo

This Problem has been solved!

You'll get a detailed, step-by-step and expert verified solution.

Join Doubtrix with 7-days free trial

  • Icon Correct & Verified Answers
  • Icon No AI-Generated Answers
  • Icon Video Solution for Difficult Questions
  • Icon Work With Experts to Reach at Correct Answers
Login Sign Up
  • Student Reviews:
  • (2)
  • Correct answers (2)
  • Complete solution (2)
  • Step-by-step solution (2)
  • Fully explained (2)

Similar/Related Questions

In one day, a 90 kg mountain climber ascends from the 1500 m level on a vertical cliff to the top at 2400 m. The next day, she descends from the top to the base of the cliff, which is at an elevation of 1270 m. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Height of a baseball from energy conservation. Part A What is her change in gravitational potential energy on the first day? Express your answer in joules. Submit Request Answer Part B What is her change in gravitational potential energy on the second day? Express your answer in joules.

Solution
0 0

A thin, 52.0 cm long metal bar with mass 750 g rests on, but is not attached to, two metallic supports in a uniform magnetic field with a magnitude of 0.440 T, as shown in ( Figure 1). A battery and a resistor of resistance 29.0 Ω are connected in series to the supports. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Magnetic force on a straight conductor. Figure 1 of 1 Part A What is the largest voltage the battery can have without breaking the circuit at the supports? Express your answer in volts. Submit Request Answer Part B The battery voltage has the maximum value calculated in part (a). If the resistor suddenly gets partially short-circuited, decreasing its resistance to 2.00 Ω, find the initial acceleration of the bar. Express your answer in meters per second squared. a = m/s2A thin, 52.0 cm long metal bar with mass 750 g rests on, but is not attached to, two metallic supports in a uniform magnetic field with a magnitude of 0.440 T, as shown in ( Figure 1). A battery and a resistor of resistance 29.0 Ω are connected in series to the supports. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Magnetic force on a straight conductor. Figure 1 of 1 Part A What is the largest voltage the battery can have without breaking the circuit at the supports? Express your answer in volts. Submit Request Answer Part B The battery voltage has the maximum value calculated in part (a). If the resistor suddenly gets partially short-circuited, decreasing its resistance to 2.00 Ω, find the initial acceleration of the bar. Express your answer in meters per second squared. a = m/s2
Solution
0 0

Two crates connected by a rope lie on a horizontal surface (Figure 1). Crate A has mass mA and crate B has mass mB. The coefficient of kinetic friction between each crate and the surface is μk. The crates are pulled to the right at constant velocity by a horizontal force F→. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Friction in horizontal motion. Figure 1 of 1 Part A In terms of mA, mB, and μk, calculate the magnitude of the force F→. Express your answer in terms of some or all of the variables mA, mB, μk, and acceleration due to gravity g. Submit Request Answer Part B In terms of mA, mB, and μk, calculate the tension in the rope connecting the blocks. Include the free-body diagram or diagrams you used to determine each answer. Express your answer in terms of some or all of the variables mA, mB, μk, and acceleration due to gravity g.

Solution
0 0