Two particles are in a uniform electric field whose value is +2500 N/C. The mass and charge of particle 1 are m1 = 1.93×10−5 kg and q1 = −7.51 μC, while the corresponding values for particle 2 are m2 = 2.98×10−5 kg and q2 = +15.9 μC. Initially the particles are at rest. The particles are both located on the same electric field line but are separated from each other by a distance d. When released, they accelerate, but always remain at this same distance from each other. Find d.
![Consider the charge distribution below. The charge values are q1 = 5 μC, q2 = −4 μC and q3 = −3 μ C. μ stands for micro. q1 and q2 are separated by a distance of 0.3 m, and q2 and q3 are also separated by a distance of 0.3 m. q2 q3 + q1 The goal of this problem is to solve for the magnitude and direction of the net force on q3 due to q1 and q2. The problem is designed to provide for partial credit due from correct process. The magnitude of the force on q3 due to q1 is [ Select ] , which has an x -component of [ Select ] and a y-component of [ Select ] The magnitude of the force on q3 due to q2 is [ Select ], which has an x -component of [ Select ] and a y-component of [ Select ] . The net force on q3 has an x -component of [ Select ] and y-component of [ Select ]. The magnitude of the net force on q3 is [ Select] , with a direction that is [ Select ] degrees as measured counterclockwise from the positive x axis.](https://www.doubtrix.com/uploads/editor/4395866419dZwYlooJMW.png)