When a 0.0622−kg golf ball takes off after being hit, its speed is 44.2 m/s. (a) How much work is done on the ball by the club? (b) Assume that the force of the golf club acts parallel to the motion of the ball and that the club is in contact with the ball for a distance of 0.0177 m. Ignore the weight of the ball and determine the average force applied to the ball by the club. (a) Number Units (b) Number Units
![A soccer player kicks a soccer ball of mass 0.45 kg that is initially at rest. The player's foot is in contact with the ball for 1.30×10−3 s, and the force of the kick is given by F(t) = [(6.68×105)t − (5.14×108)t2] N for 0 ≤ t ≤ 1.30×10−3 s, where t is in seconds. Find the magnitudes of the following: (a) the impulse on the ball due to the kick, (b) the average force on the ball from the player's foot during the period of contact, (c) the maximum force on the ball from the player's foot during the period of contact, and (d) the ball's speed immediately after it loses contact with the player's foot. (a) Number Units (b) Number Units (c) Number Units (d) Number Units (d) Number Units](https://www.doubtrix.com/uploads/editor/9236055826UBUkTxvDIR.jpg)
