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Why do observers in different reference frames disagree about the length of an object? Because moving objects are stretched by forces which make them move. Because clocks in moving frames are less accurate than clocks at rest. Because moving objects get compressed to greater density by acceleration. Because they disagree about the time of events which define the ends of the object.

Why do observers in different reference frames disagree about the length of an object? Because moving objects are stretched by forces which make them move. Because clocks in moving frames are less accurate than clocks at rest. Because moving objects get compressed to greater density by acceleration. Because they disagree about the time of events which define the ends of the object.

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Why do observers in different reference frames disagree about the length of an object? Because moving objects are stretched by forces which make them move. Because clocks in moving frames are less accurate than clocks at rest. Because moving objects get compressed to greater density by acceleration. Because they disagree about the time of events which define the ends of the object.

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A load of bricks with mass m1 = 17.0 kg hangs from one end of a rope that passes over a small, frictionless pulley. A counterweight of mass m2 = 31.0 kg is suspended from the other end of the rope, as shown in (Figure 1). The system is released from rest. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Two bodies with the same magnitude of acceleration. Part A Draw a free-body diagram for the load of bricks. Draw the vectors starting at the black dot. The location, orientation, and relative length of the vectors will be graded. The exact length of the vectors will not be graded. No elements selected Select the elements from the list and add them to the canvas setting the appropriate attributes Draw the vectors starting at the black dot. The location, orientation, and relative length of the vectors will be graded. The exact length of the vectors will not be graded. 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